Math, asked by jsubashini5590, 4 months ago

Find (295×305) using suitable Identity

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Answered by hrithikray67
5

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295*305

295*305= (300-5)*(300+5)

295*305= (300-5)*(300+5)= 300^2 - 5^2 .........( (a+b) (a-b) = a^2-b^2 )

295*305= (300-5)*(300+5)= 300^2 - 5^2 .........( (a+b) (a-b) = a^2-b^2 )= 90000 - 25

295*305= (300-5)*(300+5)= 300^2 - 5^2 .........( (a+b) (a-b) = a^2-b^2 )= 90000 - 25= 89975

hope it helps :)

Answered by s4a1574nikhil05674
1

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the correct answer was there is

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