find 2nd and 3rd term of sequence whose nth term is given by tn=2n-5
Answers
Answered by
3
tn=2n-5
t2=2(2)-5=-1
t3=2 (3)-5=1
hence 2nd and 3rd terms are -1 and 1 respectively
t2=2(2)-5=-1
t3=2 (3)-5=1
hence 2nd and 3rd terms are -1 and 1 respectively
Answered by
0
a2=2(2)-5=4-5=-1
a3=2(3)-5=6-5=1
a3=2(3)-5=6-5=1
Similar questions