find 2sin53°/cos37°=?
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2 sin 53/cos 37----
2 sin(90-37)/cos 37
2 cos 37/cos 37
using complementary identities-> sin (90- theta) = cos theta
thereby answer is 2
2 sin(90-37)/cos 37
2 cos 37/cos 37
using complementary identities-> sin (90- theta) = cos theta
thereby answer is 2
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