Question

Find (2x + 3y)2 using algebraic identities.

Answer 1

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$(a + b {)}^{2} = {a}^{2} + {b}^{2} + 2ab$

Putting a= 2x and b=3y

$(2 {x)}^{2} + (3 {y)}^{2} + 2 \times (2x)(3y)$

${{2}^{2}\times {x}^{2} + {3}^{2} \times {y}^{2} + (2 \times 2 \times 3)(x \times y)}$

$4 {x}^{2} + 9 {y}^{2} + 12xy$

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Answer 2

Answer:

4x^2 + 12xy + 9y^2

Step-by-step explanation:

(2x + 3y)^2

= identity

a^2 + 2ab + b^2 = (2x+3y)^2

So,

(2x)^2 + 2*2x*3y + (3y)^2

4x^2 + 12xy + 9y^2