find ( 2x - 3y + 4z ) ( 2x + 3y + 4z )
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3y/2x=4z/3y
=>3yz/8xz=1
=>8xz=9y2------- (i)
L.H.S=4x2+9y2+16z2
=4x2+8xz+16z2 (from i)
=(2x)2+2(2x)(4z)+(4z)2−8xz
=(2x+4z)2−9y2
=(2x+4z)2−(3y)2
Using,a2−b2=(a+b)(a−b)
=(2x+3y+4z)(2x−3y+4z)
=R.H.S
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