Question

Find
(3-2√2) ³
Need urgent.......

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Answer 1

=1/[3+2(2)^1/2]^3+1/[3-2(2)^1/2]^3

=[{3-2(2)^1/2}^3+{3+2(2)^1/2}^3]÷[{3+2(2)^1/2}^3×{3-2(2)^1/2}^3

=[{3-2(2)^1/2+3+2(2)^1/2}^3-3×{3-2(2)^1/2}{3+2(2)^1/2}{3-2(2)^1/2+3+2(2)^1/2}]÷[3^2–{2(2)^1/2}^2]

=[6^3-3(9-8)(6)]÷[9-8]

=216-18

=198