Question

find 3 4 5 sum with explanation

Answer 1

3】1] Rahim :
Given : Side of square path = 50m
No. of rounds = 2
Solution : Distance covered by Rahim = 2( Area of square path ) ...... ( No. of rounds = 2)
Distance covered by Rahim = 2( Side^2 )
= 2( 50^2)
=2( 2500 )
= 5000m
2] Peter :
Given : Length of rectangular path = 40m
Breadth of rectangular path = 30m
No. of rounds = 2
Solution : Distance covered by Peter = 2( Area of rectangular path )
Distance covered by Peter = 2 ( l × b )
= 2 ( 40 × 30 )
= 2 ( 1200 )
= 2400m
Distance covered by Rahim >
Distance covered by Peter
Distance covered by Rahim -
Distance covered by Peter = 5000 - 2400
= 2600 m

4】Given : Length of rectangular park is 14m
more than its breadth.
Perimeter of the rectangular park =
200m.
To Find : Length of the rectangular park
Area of the rectangular park.

Let the breadth of the rectangular park = x and the length of the rectangular park = x + 14

Perimeter of the rectangular park = 2( l + b )
200 = 2( x + x + 14 )
200/2 = 2x + 14
100 - 14 / 2 = x
43 = x

Breadth of the rectangular park = x
= 43
Length of the rectangular park = x + 14
= 43 + 14
= 57

Area of the rectangular park = l × b
= 57 × 43
= 2451 sq. m.

5】Given : Side of the square garden = 5m
No. of fenced rows = 2
Rate = ₹ 10 per m

Solution : Area of the square garden =
Side ^ 2
= 5 ^ 2
= 25 sq.m.

Amount required to fence the
garden at ₹ 10 per m ( 2 rows ) =
2 × 25 × 10
= ₹ 500