Math, asked by yukta4900, 11 months ago

Find 3.7 + 5.10 + 7.13 + 9.16 + .... upto n terms.

Answers

Answered by gadakhsanket
6

Hey dear,


● Answer-

Sn = 2n^3 + 17/2 n^2 + 21/2 n


● Explaination-

nth term in given series is given by-

tn = (2n+1)(3n+4)

tn = 6n^2 + 11n + 4


To calculate sum of the series-

Sn = ∑ (6n^2 + 11n + 4)

Sn = 6 ∑n^2 + 11 ∑n + 4 ∑1

Sn = 6n(n+1)(2n+1)/6 + 11n(n+1)/2 + 4n

Sn = 2n^3 + 3n^2 + n + 11/2 n^2 + 11/2 n + 4n

Sn = 2n^3 + 17/2 n^2 + 21/2 n


Therefore, sum upto n terms is 2n^3 + 17/2 n^2 + 21/2 n .


Hope this help..


Answered by vanshikabandaru
0

Answer:

answer is in the above attachment. please mark as brainliest

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