Find 3.7 + 5.10 + 7.13 + 9.16 + .... upto n terms.
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Answered by
6
Hey dear,
● Answer-
Sn = 2n^3 + 17/2 n^2 + 21/2 n
● Explaination-
nth term in given series is given by-
tn = (2n+1)(3n+4)
tn = 6n^2 + 11n + 4
To calculate sum of the series-
Sn = ∑ (6n^2 + 11n + 4)
Sn = 6 ∑n^2 + 11 ∑n + 4 ∑1
Sn = 6n(n+1)(2n+1)/6 + 11n(n+1)/2 + 4n
Sn = 2n^3 + 3n^2 + n + 11/2 n^2 + 11/2 n + 4n
Sn = 2n^3 + 17/2 n^2 + 21/2 n
Therefore, sum upto n terms is 2n^3 + 17/2 n^2 + 21/2 n .
Hope this help..
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0
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answer is in the above attachment. please mark as brainliest
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