Find 3 consecutive natural numbers such that the sum of the first and second is fifteen more than the third.
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)Find three consecutive natural numbers such that the sum of the first and the second is 15 more than the third. Hence, the three consecutive natural numbers are 16, 17 and 18.
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Solution :
Let the first consecutive number = x,
Second consecutive number = x + 1
and Third consecutive number = x + 2
According to the condition,
x+x+1=15+x+2x+x+1=15+x+2
⇒2x+1=17+x⇒2x+1=17+x
⇒2x-x=17-1⇒2x−x=17−1
⇒x=16⇒x=16
∴ The first natural number = x = 16
Second natural number = x+1 = 16+1 = 17
Third natural number = x +2 = 16 + 2=18
Hence, the three consecutive natural numbers are 16, 17 and 18.
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