Question

Find 3 consecutive numbers whose sum is 18 and their product is 120... Only concicutive number not concicutive natural number please solve it I will mark your answer as the BRAINLIEST only when I get the correct answer please answer it no spam please and please do follow me.... ​

Answer 1

Answer:

2 , 6 , 10

Let the 3 consecutive terms in the A.P. be a−d,a,a+d

Thus a−d+a+a+d=18 and also (a−d)(a)(a+d)=120 Thus, solving these two equations we get 3a=18 or a=6

Thus putting the value of a=6 in the second equation, we get

(6²-d²)(a+d)=120 or 36−d

2

=20

Or d=+/−4

Thus the three consecutive terms in the A.P. are 2,6,10

Answer 2

Answer:

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