Question

find 3 consecutive numbers whose sum os 27 plz answer it with full explanation full explanation​

Answer 1

Answer:

1st number 8

1st number 82nd number 9

1st number 82nd number 93rd number 10

Step-by-step explanation:

Consecutive numbers

Sum of the Numbers = 27

1st number = x

2nd number = x + 1

3rd number = x + 2

Therefore = x + x + 1 + x + 2= 27

= 3x + 3 = 27

Transposition = 3x = 27- 3

3x = 24

Transposition = x = 24/3

x = 8

Therefore 1st number = 8

2nd number : x + 1 = 8 + 1 = 9

3rd number : x + 2 = 8 + 2 = 10

Verification : 10 + 9 +8 = 27

Answer 2

Step-by-step explanation:

let the all three consecutive no be x,x+1,x+2

x+x+1+x+2=27

3x+3=27

subtracting 3 from both sides

3x+3-3=27-3

3x=24

Now dividing 3 on both the sides

3x/3=24/3

x=8

x=8

x+1=8+1=9

x+2=8+2=10