Question

Find 3 consecutive term in ap whose sum is -3 and product of their cube is 512

Answer 1

Answer:

-4 , -1 & 2

Step-by-step explanation:

let say 3 numbers are

a-d , a  , a+d

Sum = 3a = -3

so a = -1

numbers are

-1-d , -1 , -1+d

{-(1+d)(-1)(d-1)}^3 = 512

d^2 -1 = 8

d ^2 = 9

d = +/-3

so numbers are

-4 , -1 , 2