Math, asked by pushpasanjaygowda, 1 month ago

find 3 consecutive terms in AP whose sum is 80 and sum of their squares is 140

Answers

Answered by singhanshika1102

0

Answer:

a-d=-4.9033613

a=26.666667

a+d=58.2366947

Step-by-step explanation:

a-d+a+a+d=80

3a=80

a=80/3=26.666667

A2+D2-2ad+A2+A2+D2+2ad=140

3a2+2d2=140

3(80/3)(80/3)+2d2=140

2d2=140-6400/3

2d2=420-6400/6

D2=-5980/6

d=31.570028

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