Question

find 3 consecutive terms of an A.p whose sum is -37 and the products of their cubes is ​

Answer 1

Answer:

Let the numbers be (a−d),a,(a+d). Then,

Sum=−3⇒(a−d)+a+(a+d)=−3⇒3a=−3⇒a=−1

Product of their cubes=512⇒(a−d)

3

×a

3

×(a+d)

3

=512

⇒(a

2

−d

2

)

3

×a

3

=512

⇒−(1−d

2

)

3

=512 (∵a=−1)

⇒−(1−d

2

)=8

⇒d

2

=9⇒d=±3

If d=3, then the numbers are −4,−1,2. If d=−3, then the numbers are 2,−1,−4.

Step-by-step explanation:

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Answer 2

same to you pullal

Sunni.