find 3 consecutive whose sum is 45
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Answered by
1
Let 1st number be x
2nd number be x+1
3rd number be x+2
Now x+x+1+x+2= 45
3x + 3 = 45
3x = 45-3
3x = 42
x= 42/3
x= 14
Therefore x =14
x+1= 14+1=15
x+2=14+2=16
2nd number be x+1
3rd number be x+2
Now x+x+1+x+2= 45
3x + 3 = 45
3x = 45-3
3x = 42
x= 42/3
x= 14
Therefore x =14
x+1= 14+1=15
x+2=14+2=16
Answered by
1
Answer:
HELLO MATE HERE IS YOUR ANSWER
LET THE FIRST NUMBER BE x
ACC. To question
x + ( x + 1 ) + ( x + 2 ) = 45
3x + 3 = 45
3x = 45 - 3
3x = 42
x = 42/3
x = 14
HOPE IT HELPS!!!
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