Question

find 3 consicutv integers such tht 3rd is 1 and a half times the 1st.. plzz ansr fst today evng is my tution

Answer 1

let the three consecutive numbers be (n-1),n,&(n+1) , then ;

(n+1) = 1 &(1/2) × (n-1)
(n+1) = (3/2) × (n-1)
n+1 = (3/2)n - (3/2)
1-(3/2) = (3/2)n - n
5/2 = (1/2)n
n = 5

The respective the consecutive numbers will be :
(1) (n-1) = 5-1 = 4
(2) n = 5
(3) (n+1) = 5+1 = 6

hence your answer is 4,5,6.


hope this helped you ......