Question

find 3 consiquitive natural number such that 1/2 of the smallest,1/3 of the middle one 1/4 of the largest add up to 16. pls explain it​

Answer 1

Answer:

Step-by-step explanation:

Let the numbers be x, x+1, x+2

∴1/2(x)+1/3(x+1)+1/4(x+2)=16

⇒x/2+(x+1)/3+(x+2)/4=16

⇒lcm of 2,3,4=12

⇒$\frac{6x}{12}$+$\frac{4x+4}{12}$+$\frac{3x+6}{12}$=16

⇒6x+4x+4+3x+6=16×12

⇒13x+10=192

⇒13x=182

⇒x=14

⇒x+1=15

⇒x+2=16

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