Question

find 3 different solutions of 2x + 3y = 20​

Answer 1

1st x=10 and y= 0

2nd x= -4 and y= 8

3rd x= 12 and y= -2

Answer 2

when x = 1, so 2×1 + 3y = 20

y = 6(1,6)

when x = 2 , so 2×2 + 3y =20

y = 5.33 (2,5.33)

when x = 3, so 2×3 + 3y = 20

y = 4.66 (3,4.66)