Question

find 3 different solutions of the each of the following equations 1. 3x+4y=7​

Answer 1

Answer:

i) 3x +4y = 7

put x = 0 , y = 7/4

put y = 0, x = 7/3

ii) solutions are (0,0) , (1,6) , (2,12)

iii) 2x = 7+y

=> put x = 0 , y = -7

=> put x = 1 , y = -5

hope it helps buddy

Answer 2

solutions are ( 1, 1 ) (-3, 4) and

(5, -2)

Step-by-step explanation:

3x+4y=7

4y=7 - 3x

$y = \frac{7 - 3x}{4}$

put x=1

$y = \frac{7 - 3}{4} = \frac{4}{4} = 1$

put x = -3

$y = \frac{7 + 9}{4} = \frac{16}{4} = 4$

put x = 5

$y = \frac{7 - 15}{4} = \frac{ - 8}{4} = - 2$

solutions are ( 1, 1 ) (-3, 4) and (5, -2)