Question

find 3 groups of 4 co prime numbers such that product of numbers in each of hem is 44880

Answer 1

Answer:

heay!!

Step-by-step explanation:

here,

I’m not sure what the question means, but each pair of the numbers:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997

hope you find the required pair!!

hope it helps!!

mark as brainliest

Answer 2

QUESTION:-Number of ways in which 38808 can be expressed as a product of 2 coprime factors?

ANSWER:-the answer given is 8 ways, what I did was,

38808=23×32×72×11

so the number of ways of expressing 38808 as product of 2 co-prime factors should be

8⋅(9.49.11)

9⋅(8.49.11)

49⋅(9.8.11)

11⋅(9.49.8)

hence 4, but the answer is 8, am i missing some other co-prime factor pairs