Find 3 number in AP whose sum is 15 and product 80
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Answered by
2
Answer:
hereu go......
Step-by-step explanation:
leta−d,a,a+darethreetermsofanAP
accordingtotheproblemgiven,
sumoftheterms=15
a−d+a+a+d=15
3a=15
a=
3
15
a=5
product=80
(a−d)a(a+d)=80
(a²−d²)a=80
(5²−d²)5=80
25−d²=80/5
25−d²=16
−d²=−9
d²=3²
d=±3
Therefore,a=5,d=±3
required3termsare
a−d=5−3=2
a=5
a+d=5+3=8
(2,5,8)or(8,5,2)
Answered by
0
Answer:
a−d+a+a+d=15
3a=15
a=
3
15
a=5
product=80
(a−d)a(a+d)=80
(a²−d²)a=80
(5²−d²)5=80
25−d²=80/5
25−d²=16
−d²=−9
d²=3²
d=±3
Therefore,a=5,d=±3
required3termsare
a−d=5−3=2
a=5
a+d=5+3=8
(2,5,8)or(8,5,2)
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