Question

Find 3 numbers in a gp whose sum is 9 and product is 216

Please send me fast, I will mark brainliest if correct​

Answer 1

Let three numbers be a/r ,a and ar .

a/r+a+ar=19......(1)

a/r×a×ar=216

a^3=216

a=6.......(2)

from 1). 6/r+6+6r=19

6r^2-13r+6=0

6r^2-9r-4r+6=0

3r(2r-3)-2(2r-3)=0

(3r-2)(2r-3)=0

so r=2/3,3/2.

case1) when r=2/3,a=6 then numbers :9,6,4

case2) : when r=3/2,a=6 then numbers :4,6,9

Thank you........

Hope it helps........

Please mark me as brainliest if you found this answer helpful........