Question

find 3 numbers in an AP whose sum and product is 6

Answer 1

Answer:

Step-by-step explanation:

1,2,3

1+2+3=6

1*2*3=6

Answer 2

lets say it first term is =( a- d)

2nd term is (a)

and 3rd term is (a + d)

sum is 6 so

a-d + a +a + d = 6

3a =6

a = 2

product is 6 so

(a-d)(a)(a+d) =6

putting a= 2

(2-d)(2+d) = 6/2

4-d^2 = 3

d^2 = 1

d = +1 and d = -1

so for d = -1

numbers are

(2-(-1)), (2 ) , (2 -1)

3, 2 , 1

for d =1

(2-1), (2), (2+1)

1, 2,3

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