Question

find 3 numbers in AP such that their sum is 27 and the sum of their square is 341​

Answer 1

Step-by-step explanation:

let say those numbers are

a-d, a, a+d

so

a-d+a+a+d=27

3a=27

a=27/3=9

a=9

and sum of their squares

(9-d) ^2+81+(9+d)^2=341

81-18d+d^2+81+18d+d^2+81=341

2d^2 =341-243=98

d^2= 98/2=49

d^2=49

d=-7 and +7

so the numbers are

9-(-7)=16

9

9+(-7)=9-7=2

if d =7 then

9-7=2

9

9+7=16