Question

find 3 numbers in Ap whose sum is 27 and product is 648

Answer 1

this is you all wanted if any doubt pls comment

Answer 2

Let,
Three numbers are 

1)  a-d 
2)  a 
3) a + d 

===================================

According to the condition,

a -d + a + a + d = 27 

a + a + a = 27 

3a = 27 

a = 27/3 

a = 9 

-----------------------------------------------------------

Then, Given that their Product is 648

(a - d) × a × (a + d) = 648

       Putting the value of a,

( 9- d ) × 9 × (9 + d) = 648 

(81 - 9d) × (9 + d) = 648

729 - 81d + 81d - 9d² = 648 

-9d² = 648 - 729 

-9d² = -81 

9d² = 81

d² = 81/9 

d² = 9 

d = 3    Or  -3 

====================================


Numbers are,

1)  (a -d) = 9 - 3 = 6 
2)  (a) = 9 
3)  (a + d) = 9 + 3 = 12 

-----------------------------------

                   Or,

1) (a -d ) = 9  - (-3) = 9 + 3 =  12 

2)  (a) = 9 

3) (a + d) = 9 + (-3) = 9 - 3 = 6 





i hope this will help you


-by ABHAY