Question

find 3 numbers such that the second is twice the first the third is three times the first and their sum 180
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Answer 1

Answer:

the numbers are 30,60 and 90.

Step-by-step explanation:

let the 3 numbers be a,b and c.

Given,

second is twice the first => b = 2a

third is three times the first => c = 3a

Sum of a,b and c = 180

a + b + c = 180

a + 2a + 3a = 180

6a = 180

a = 180/6

=> a = 30

b = 2a = 2(30)

=> b = 60

c = 3a = 3(30)

=> c = 90