Math, asked by ram7570, 6 months ago

find 3 numbers such that the second is twice the first the third is three times the first and their sum 180
plz fast ​

Answers

Answered by jainananya0104
0

Answer:

first number=30

second =60

third=90

Step-by-step explanation:

let the first number be x

so,

x+2 times of x+3 times of x=180

x+2x+3x=180

6x=180

x=180/6

x=30

similarly- 2x= 2 into 30=60

              3x= 3 into 30=90

so the numbers are 30 ,60 and 90

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