find 3 solutions of linear equation 7x minus 5y=35 in two variables
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7x-5y=35
x=35-5y/7
i) when y=0
x=35-5*0/7= 35/7=5 (5,0)
ii) when y=14
x=35-5*14/7=35-70/7=-35/7=-5 (-5,14)
iii) when y= 7
x=35-5*7/7=35-35/7=0/7=0 (0,7)
(5,0); (-5,14); (0,7)
x=35-5y/7
i) when y=0
x=35-5*0/7= 35/7=5 (5,0)
ii) when y=14
x=35-5*14/7=35-70/7=-35/7=-5 (-5,14)
iii) when y= 7
x=35-5*7/7=35-35/7=0/7=0 (0,7)
(5,0); (-5,14); (0,7)
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