Question

find 3 X + 4 y whole square using identity 1​

Answer 1

Answer:

$9x^{2} +24xy + 16y^{2}$

Explanation:

$(a+b)^{2} = a^{2} + 2ab + b^{2}$

Replacing a with 3x and b with 4y,

$(3x+4y)^{2} = (3x)^{2} + 2*3x*4y + (4y)^{2}$

= $9x^{2} +24xy + 16y^{2}$

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