Find 30 − 20 for the AP , + , + 2, + 3, … … ..
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Here the first term is a and the common difference is d.
Now, a
n
=a+(n−1)d
∴a
20
=a+19d ...(1)
a
30
=a+29d ...(2)
On subtracting (1) from (2), we get
a
30
−a
20
=10
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