find 30/x-y. + 28/x+y =7. 21/x+y + 21/x+y=5
Answers
Answer:
See,
Substitute 1/x-y as p
and 1/x+y as q
The equations would be then
30p +28q = 7
21p + 21q = 5
Solve for p and q. You can do it, right?
After getting values of p and q,
Resubstitute,
1/x-y = p
i.e. x-y = 1/p ....(1)
1/x+y =q
i.e. x+y =1/q....(2)
You can now solve equation 1 and 2 to get x and y
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Step-by-step explanation:
see
substitute 1/x-y as A and 1/x+y as B
now,
30A + 28B =7 - 1
21A + 21B =5 - 2
multiplying 1 by 7 and 2 by 10
we get,
210A + 196B = 49 -3
210A + 210B = 50 -4
by subtracting 2 from 1
we get,
14B = 1
B = 1/ 14
now,
by 3 we get,
210A + 196(1/14) = 49
210A = 49 - 196 (1/14 )
210A = 35
A = 1/6
now,
1/x-y = A 1/x+y = B
1/x-y = 1/6. 1/x+y = 1/14
by reciprocal,
x-y=6 - 5 x+y = 14 - 6
adding 5 and 6,
2x = 20
x = 10
by 6,
10+y=14
y = 4
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