find 30m term of 10, 7, 4...
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Solution
Given sequence is 10 , 7 , 4
First Term(a) = 10
Common difference (d) is a₂ - a₁ = 7 - 10 = -3
Number of term (n) is 30
Formula
Tₙ = a + ( n - 1 )d
By putting the value on formula we get
⇒T₃₀ = 10 + ( 30 - 1)(-3)
⇒T₃₀ = 10 - 29 × 3
⇒T₃₀ = 10 - 87
⇒T₃₀ = -77
Answer is -77
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