Question

find 30th term of an AP -3,-1/2,2..​

Answer 1

Step-by-step explanation:

n=30

a=-3

d=-1/2-(-3)

d=-5/2

tn=a+(n-1 )d

t30= -3+(30-1)5/2

=-3+29×5/2

=-3+72.5

= 69.5

Answer 2

QUESTION:

find 30th term of an AP -3,-1/2,2..

ANSWER:

We use the formula here;

$\huge\red {nth \: term = a + (n - 1)d}$

where ,

a = first term

d = common difference

now come to main question ;

Here;

first term = -3

common difference = -1/2-( -3)

= 5/2

Using the formula;

$t(30) = - 3 + (30 - 1) \times \frac{5}{2} \\ t(30) = - 3 + 29 \times \frac{5}{2} \\ t(30) = - 3 + \frac{145}{2} \\ t(30) = \frac{ - 6 + 145}{2} \\ t(30) = \frac{139}{2}$

FINAL ANSWER :

$t(30) = \frac{139}{2}$

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