Find 31 term of an AP whose 10th term is 31 and 18th term is 87
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a10 = 31
a+9d=31 -1
a18=87
a+17d=.87 -2
subtractingeq1and2
a+9d=31
a+17d=87
we get -8d= -56
d= 7
putting value in eq1
a+9d=31
a+ 9×7=31
a=31-63
a= -32
a31 = a+30d
= -32+30×7
=-32+210
= 178
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