Question

find 31st term of an AP Whose 10th term is 38and 16th term is 9​

Answer 1

Answer:

let a be the first term and d be the common difference

10th tem= a+9d. ........i

38=a+9d

and

16th term = a+15d = 9.......ii

on solving i and ii

a= 163/2

d= -29/6

31st term = a+ 30d

=. 163/2 + 30×(-29/6)

= -127/2

hope this will help u...

Answer 2

Check the attachment for solution