Math, asked by robinj23, 1 year ago

find 31st term of an ap whose 11th term is 38 and the 16th term is 73

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Answered by Amankhan993653
9
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Answered by kumarramchander84
2

Answer 178  Tn=a+(n-1)d Tn11=a+10d=38 first equation Tn16=a+15d=73 second equation   Subtract eq1 andeq2 +A+10d=38 -A+15d=-73       5d=35          d=35/5           d=7 Put the value of d in equation 1    a+10d=38    a+10×7=38     a+70=38      a=38-70      a=-32 A=-32 ,D=7,N=31      -32+(31-1)×7      -32+(30)×7       -32+210        178                               31st term is 178

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