Question

find 31st term of an AP whose11th term is 38 and 16 term is 73.
plzz hlp me i need this solution soon...​

Answer 1

Step-by-step explanation:

38=a+10d

73=a+15d

35=5d

d=7

73=a+105

a=-32

t31=-32+(31-1)x7

t31=-32+210

t31=178 (:: OK friend this is urs answer

Answer 2

Step-by-step explanation:

given

t11=38

t16=73

tn=a+(n-1)d

t11=a+10d

38=a+10d--------------1

t16=a+15d

73=a+15d---------------2

eqn2 - eqn1

35=5d

d=7

put value of d in eqn1

38=a+70

a=-32

t31=-31+30x7

=-31+210

=179