Question

Find 36 th tearm of ap 112,109,106,103

Answer 1

Answer:

112,109,106,103..............

a=112,d=109-112=-3,n=36

nth term=a+(n-1)d

=112+(36-1)(-3)

=112+35(-3)

=112-105=7

Answer 2

Answer:

$\huge{\pink{\green{\sf{\therefore a_{36}=7}}}}$

Step-by-step explanation:

$\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}$

• In the given question information given about an A.P.

• So,we have to find the given term.

• According to given question :

$\underline \bold{given : } \\ \bold{\implies a.p = 112,109,106,103,...} \\ \bold { \implies a = 112} \\ \bold { \implies d = - 3} \\ \\ \underline \bold{to \: find : } \\ \bold { a_{36} = ? }$

▪Shortcut method to find any term of a series is first term + 1 less than the given terms multiply d.

》For example :

• a23 = a + 22d

• a34 = a + 33d

$\bold{by \: formula : } \\ \implies a_{n} = a + (n - 1)d \\ \implies a_{36} = 112 + (36 - 1) \times ( - 3 )\\ \implies a_{36} = 112 + 35 \times ( - 3) \\ \implies a_{36} = 112 - 105 \\ \bold {\therefore a_{36} = 7} \\ \\ \bold{shortcut \: method :} \\ \implies a_{36} = a + 35d \\ \implies a_{36} = 112 + 35 \times (- 3) \\ \implies a_{36} = 112 - 105 \\ \bold{\therefore a_{36} = 7}$