find 3consecutive even natural numbers such that 7times the middle number is 42less than 4times the other 2?
shameemamk:
Is it 4 times the sum of other two?
yes
Answers
Answered by
1
Let the 3 consecutive even numbers be "x-2", "x", "x+2".
Consecutive Even or Odd numbers, differ by 2, for eg: 2, 4(= 2+2), 6(= 4+2).
OR
These numbers, (2, 4, 6) can also be written as, (4-2), 4, (4+2).
So, now According to Question:
7×(middle number) = 4×(other 2) - 42
Now, solve it.
7×(x) = 4×[(x-2) + (x+2)]
Thankyou!!!
Consecutive Even or Odd numbers, differ by 2, for eg: 2, 4(= 2+2), 6(= 4+2).
OR
These numbers, (2, 4, 6) can also be written as, (4-2), 4, (4+2).
So, now According to Question:
7×(middle number) = 4×(other 2) - 42
Now, solve it.
7×(x) = 4×[(x-2) + (x+2)]
Thankyou!!!
Answered by
2
Answer: 40, 42 and 44
Step-by-step explanation:
Please see the attached explanation
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