Question

Find 3consecutive no. such that the sum of the second and third number exceed the first by 14

Answer 1

Question :-

Find 3 consecutive number such that the sum of the second and third number exceed the first by 14.

Assumption :-

• Let the consecutive numbers the x, x+1 and x+2

Solution :-

According to the question :-

⇒ second no. + third no. - first no. = 14

⇒ (x+1) + (x+2) - x = 14

⇒ x+1+x+2-x = 14

⇒ x+3 = 14

⇒ x = 14-3

∴ x = 11

Answer :-

• The three consecutive numbers are :-

⇒ x = 11

⇒ x+1 = 12

⇒ x+2 = 13

Verification :-

⇒ second no. + third no. - first no. = 14

⇒ 12 + 13 - 11 = 14

⇒ 25-11 = 14

⇒ 14 = 14

★ hence, verified ✓

Answer 2

Understanding by easy method:

Let the number be x, x+1 ,x+2 are 3 consecutive numbers.

According to the question

(second no. +third no.-first no. =14)

•$(x+1)+(x + 2)-x=14$

•$x+1+x+2-x=14$

•$x+3 =14$

•$x=14-3$

=11

Therefore,

First number = x=11

Second number = x+1=11+1=12

Third number = x+2=11+2=13

The numbers are, 11, 12 and 13.

Verification:

(second+third-first=14)

•12+13-11=14

•25-11=14

=14=14

★Hence, Verified ✓