Question

Find 3consecutive odd numbers such that the sum of twice the least number and thrice the greatest number is 107

Answer 1

Let one odd number be x

Let three consecutive odd numbers are x-2,x,x+2

Least number is x-2

Twice of x-2=2 (x-2)=2x-4

Greatest number is x+2

Thrice of x+2=3 (x+2)=3x+6

Sun of above numbers

=2x-4+3x+6=5x+2

Since Sum of those two numbers =107

Therefore,

5x+2=107

=5x=105

=x=21

Hence there numbers are

x=21

x-2=21-2=19

x+2=21+2=23

I hope it will help you ☺