Find 3consecutive odd numbers such that the sum of twice the least number and thrice the greatest number is 107
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Let one odd number be x
Let three consecutive odd numbers are x-2,x,x+2
Least number is x-2
Twice of x-2=2 (x-2)=2x-4
Greatest number is x+2
Thrice of x+2=3 (x+2)=3x+6
Sun of above numbers
=2x-4+3x+6=5x+2
Since Sum of those two numbers =107
Therefore,
5x+2=107
=5x=105
=x=21
Hence there numbers are
x=21
x-2=21-2=19
x+2=21+2=23
I hope it will help you ☺
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