Find 3numbers of AP whose sum is 27 and product is 648
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let the terms be (x-a), x , (x+a)
sum of the 3 terms =27
x+a+x+x-a=27
3x=27
x=9
(x+a)*x*(x-a)=648
(9+a)*(9-a)=648/9
(9∧2-a∧2)=72
a=√(81-72)
a=3
the terms are 9-3 , 9 , 9+3= 6,9,12
sum of the 3 terms =27
x+a+x+x-a=27
3x=27
x=9
(x+a)*x*(x-a)=648
(9+a)*(9-a)=648/9
(9∧2-a∧2)=72
a=√(81-72)
a=3
the terms are 9-3 , 9 , 9+3= 6,9,12
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