Question

Find 3p – 4q + 7r – pqr when p = 1, q = 2, r = 3. b)​

Answer 1

Answer:

3p-4q+7r-pqr

Put the values of p=1 q=2 and r=3

3p-4q+7r-pqr

=3(1)-4(2)+7(3)-1×2×3

=3-8+21-6

=10

Answer 2

Answer:

10

Step-by-step explanation:

Given equation is 3p - 4q + 7r - pqr

Where p = 1, q = 2 and r = 3

Putting the values of p, q and r in the equation we get,

3 x 1 - 4 x 2 + 7 x 3 - 1 x 2 x 3

Now Solving it by BODMAS rule we get,

=> 3 - 8 + 21 - 6

=> 10

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