Math, asked by sreekari36, 1 year ago

find (3x-4y)whole square

Answers

Answered by ashish5597
14
whole square of (3x-4y)
= (3x-4y)^2
= (3x)^2 + (4y)^2 - 2(3x)(4y)
=9x^2 +16y^2 -24xy
Answered by farzanavyr
3

ANSWER

whole sqare of (3x-4y) =(3x-4y)^2=(3x)^2+(4y)^2 2(3x) (4y)=9x2+16y2 -24xy

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