Question

Find 3x cube + 6x square + 3x +4. If the value of x = (-1)

Answer 1

Answer:

4

Step-by-step explanation:

given

$3 {x}^{3} + 6 {x}^{2} + 3x + 4 \\ \\ x = - 1 \\ \\ 3 {( - 1)}^{3} + 6 {( - 1)}^{2} + 3( - 1) + 4 \\ \\ = - 3 + 6 - 3 + 4 \\ \\ = 4$

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Answer 2

The value of the given polynomial is 10

Step-by-step explanation:

given equation :

$3x^3+6x^2+3x+4$

where x = -1

place the value of x= -1 in the polynomial

then

$3x^3+6x^2+3x+4$

= 3(-1)³ + 6(-1)²+3(-1) +4

= -3 +6 -3 +4

= 10

hence , The value of the given polynomial is 10

#Learn more:

If one of the zeroes of the polynomial ax square + 6x + 2 is -1, find the value of a

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