Question

Find (4.9)square using 2 identity

Answer 1

Answer:

24.01

Step-by-step explanation:

(4.9)^2=(5-0.1)^2

(a-b)^2=a^2-2ab+b^2

(5-0.1)^2=5^2-2(5)(0.1)+(0.1)^2

=25-1+0.01=24.01

Answer 2

Step-by-step explanation:

The two identities which we can use to find the square of 4.9 are:-

→ (a+b)² = a² + 2ab + b²

→ (a-b)² = a² - 2ab + b²

Now, using (a+b)² = a² + 2ab + b²:-

• We, can also write 4.9 as (4 + 0.9).

→ (4.9)² = (4+0.9)²

→ (4+0.9)² = (4)² + 2×4×0.9 + (0.9)²

→ (4+0.9)² = 16 + 7.2 + 0.81

→ (4+0.9)² = 24.1

Therefore, (4.9)² is equal to 24.1 using (a+b)² = a² + 2ab + b²

Now, using (a-b)² = a² - 2ab + b²:-

• We, can also write 4.9 as (5 - 0.1).

→ (4.9)² = (5 - 0.1)²

→ (5 - 0.1)² = (5)² - 2×5×0.1 + (0.1)²

→ (5 - 0.1)² = 25 - 1 + 0.1

→ (5 - 0.1)² = 24.1

Therefore, (4.9)² is equal to 24.1 using (a-b)² = a² - 2ab + b²

Please mark as “Brainliest Answer”....