find 4 consective terms in ap whose sum is 12 and sum of 3 and 4.term is 14
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let the four consecutive terms of AP BE
a-3d, a-d, a+d,a+3d
then sum of terms a-3d + a -d +a+d +a+3d =4a= 12
thus a=12/4=3
sum of 3 and 4 the term is 14
a+d. + a+3d =14
2a+4d=14
6+4d=14. (a=3)
4d=14-6=8
d= 2
thus first four terms are
a-3d=3-6 = -3
a-d= 3-2= 1
a+d = 3+2= 5
a+2d = 9
you can also take in the starting as the first four terms as a+d, a+2d, a+3d, a+4d
please mark answer brainliest
a-3d, a-d, a+d,a+3d
then sum of terms a-3d + a -d +a+d +a+3d =4a= 12
thus a=12/4=3
sum of 3 and 4 the term is 14
a+d. + a+3d =14
2a+4d=14
6+4d=14. (a=3)
4d=14-6=8
d= 2
thus first four terms are
a-3d=3-6 = -3
a-d= 3-2= 1
a+d = 3+2= 5
a+2d = 9
you can also take in the starting as the first four terms as a+d, a+2d, a+3d, a+4d
please mark answer brainliest
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