Question

find 4 consecutive even integers such that the sum of the first exceed the fourth by 8

Answer 1

1st 2x
2nd 2x+2
3rd 2x+4
4th 2x+6
EQUATION
6x+6=2x+6+8
6x-2x=6+8+6
4x=8
4x/4=8/4(divide both sides by 4)
x=2
1st=2x
=2(2)
=4
2nd=2x+2
=2(2)+2
=4+2
=6
3rd=2x+4
=2(2)+4
=4+4
=8
4th=2x+6
=2(2)+6
=4+6
=10
four consecutive integers are 4 6 8 10
bysudhir