Find 4 consecutive terms in an AP such that their sum is -40 and the sum of first and third term is -18
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A] Let three numbers be a - d, a, a + d
given
a - d + a + a + d = 21
3a = 21
∴a=7
(a + d) (a - d) a = 315
=(7+d)(7−d)×7=315
=(7
2
−d
2
)=45
=7
2
−45=d
2
=49−45=d
2
=4=d
2
d=±2
numbers are
7 - 2 , 7 , 7 + 2
= 5 , 7 , 9
Step-by-step explanation:
A] Let three numbers be a - d, a, a + d
given
a - d + a + a + d = 21
3a = 21
∴a=7
(a + d) (a - d) a = 315
=(7+d)(7−d)×7=315
=(7
2
−d
2
)=45
=7
2
−45=d
2
=49−45=d
2
=4=d
2
d=±2
numbers are
7 - 2 , 7 , 7 + 2
= 5 , 7 , 9
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