Question

Find 4 consecutive terms in AP whose sum is 40

Answer 1

Answer:

the consecutive terms are 7,9,11,13

Step-by-step explanation:

let the 4 consecutive terms be

          a-3d , a-d , a+d , a+3d

sum=40

 i.e.=>a+3d+a+d+a-d+a-3d=40

     =>  4a=40                           (subtracting all the 'd's..)

     =>    a=10

d=1   (given)

   ∴ the consecutive terms are    7 , 9 , 11 , 13 ...

pls mark this as brainliest....

Answer 2

Answer:

.......................

Step-by-step explanation: