Find 4 consecutive terms in AP whose sum is 40
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Answered by
1
Answer:
the consecutive terms are 7,9,11,13
Step-by-step explanation:
let the 4 consecutive terms be
a-3d , a-d , a+d , a+3d
sum=40
i.e.=>a+3d+a+d+a-d+a-3d=40
=> 4a=40 (subtracting all the 'd's..)
=> a=10
d=1 (given)
∴ the consecutive terms are 7 , 9 , 11 , 13 ...
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Answered by
0
Answer:
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Step-by-step explanation:
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